It's huge!

Logic Level 2

Is it possible?

$0 ~ ~ 0 ~ ~ 0 = 6$

$1 ~ ~ 1 ~ ~ 1 = 6$

$2 ~ ~ 2 ~ ~ 2 = 6$

$3 ~ ~ 3 ~ ~ 3 = 6$

$4 ~ ~ 4 ~ ~ 4 = 6$

$5 ~ ~ 5 ~ ~ 5 = 6$

$6 ~ ~ 6 ~ ~ 6 = 6$

$7 ~ ~ 7 ~ ~ 7 = 6$

$8 ~ ~ 8 ~ ~ 8 = 6$

$9 ~ ~ 9 ~ ~ 9 = 6$

Rules: Any operations can be used!

Yes No

1 solution

Munem Shahriar
Aug 9, 2017

$(0!+0!+0!)! = 6$

$(1!+1!+1!)! = 6$

$2+2+2 = 6$

$3 \times 3-3= 6$

$4+4 - \sqrt{4} = 6$

$5+5 \div 5 = 6$

$(6+6) - 6 = 6$

$7-7\div 7 = 6$

$8- \sqrt{\sqrt{(8+8)}} = 6$

$(9+9) \div \sqrt{9} = 6$

Therefore it is $\color{#20A900} \boxed{\text{possible}}$

You have a typo. 3x3-3=6 not 5.

Siva Budaraju - 3 years, 10 months ago

Thanks...........

Munem Shahriar - 3 years, 10 months ago

that's a great question.after a long time i am unsuccessful to answer a level 2 question.

Mohammad Khaza - 3 years, 10 months ago