Find the term independent of in expansion of
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Such problems look bizarre at first sight. But on second sight we can easily simplify it as, ( x 1 / 3 − x − 1 / 2 ) 1 0
Whose independent term would be- ( 6 1 0 ) ( x 1 / 3 ) 6 × ( x − 1 / 2 ) 4 ⟹ coefficient of independent term = 2 1 0