It's not 30

Find the smallest non-negative integer such that when it is divided by 2, 3 or 5, the remainder is 0.


The answer is 0.

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1 solution

Munem Shahriar
Jan 12, 2018

The LCM of 2,3 and 5 is 30. So 30 can satisfy the condition.

But we know that for a R a \in \mathbb{R} and a 0 , a \ne 0, 0 a = 0 \dfrac{0}{a} = 0 . Hence the smallest non-negative integer that is divisible by 2, 3 and 5 is 0.

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