Two identical right circular cones each of height 2 cm are placed vertical apex downward.At the start, the upper cone is full of water and lower cone is empty.Then water drips down through a hole in the apex of upper cone into the lower cone. The cube of height of water in the lower cone at the moment when height of water in upper cone is 1 cm is:
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The volume of water in an inverted cone is given by V = 3 1 π r 2 y , where r is the base radius and y is the height from the vertex. It is noted that r ∝ y ⇒ V ( y ) ∝ y 3 .
Let the full cone of water be V f , therefore, V f V ( y ) = 2 3 y 3 ⇒ V ( y ) = 8 y 3 V f .
The water volume of top cone, V ( 1 ) = 8 1 V f . And the water in the bottom cone V ( y b ) = V f − 8 1 V f = 8 7 V f = 8 y b 3 V f ⇒ y b 3 = 7