Its obviously squared, right?

First instinct is to think that $16 \le x^2 \le 49$ . But the numbers lying in $-4 \lt x \lt 4$ will not satisfy the assumed range. Since $x \in \mathbb{R}$ , the minimum value of $x^2$ will be $0$ , and hence the range will be $0 \le x^2 \le 49$ . Thus the answer is $\boxed{\color{#D61F06}{0+49}=\color{#3D99F6}{49}}$