It’s scandalous! #2

If by "spheres" the problem writer means "balls," then the force of attraction between the two balls is given by the product of $\frac{q_1q_2}{4\pi\epsilon_0}$ and a sextuple integral that I do not wish to take the time to express, assuming the charge is spread evenly across the balls. In both cases, the sextuple integral is the same. The only things that change are $q_1$ and $q_2$ . The charges are unlike to begin with so the force is attractive. My belief is that, when the balls touch, the charges average out. So, $\frac{A}{B} = \frac{0.6\times 10^{-19}\times -8\times 10^{-19}}{(\frac{0.6\times 10^{-19}+-8\times 10^{-19}}{2})(\frac{0.6\times 10^{-19}+-8\times 10^{-19}}{2})}\approx -0.3506$ . Therefore, force $B$ is repulsive and greater in magnitude than force $A$ . Scandalous indeed.