It's still possible to do it by hand
33, 34, 35 is the smallest triplet of consecutive positive integers such that they each have a precisely 4 positive divisors .
Find the fourth smallest positive integer such that the numbers has precisely 4 positive divisors each.
The answer is 141.
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1 solution
def problem1239343():
count=0
for i in range(33,200):
if prime(MinFactor(i)) and prime(i//MinFactor(i)):
count+=1
else:
count=0
if count==3:
print(i)