It's too complex.

Algebra Level 3

If z 1 , z 2 , z 3 z_1, z_2, z_3 are three complex numbers such that

z 1 = z 2 = z 3 = 1 z 1 + 1 z 2 + 1 z 3 = 1 \left|z_1\right| = \left|z_2\right| = \left|z_3\right| = \left|\frac{1}{z_1}+\frac{1}{z_2}+\frac{1}{z_3}\right| = 1 ,

then z 1 + z 2 + z 3 \left|z_1+z_2+z_3\right| is

6 0 1 3

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1 solution

Rohit Sharma
Jul 1, 2017

We have z 1 = z 2 = z 3 = 1 z 1 + 1 z 2 + 1 z 3 = 1 \left|z_1\right| = \left|z_2\right| = \left|z_3\right| = \left|\frac{1}{z_1}+\frac{1}{z_2}+\frac{1}{z_3}\right| = 1

Now , we know z 1 2 = z 1 . z 1 = 1 \left|z_1\right|^2 = z_1.\overline{z_1} = 1

\therefore z 1 = 1 z 1 \overline{z_1} = \frac{1}{z_1}

Similarly , z 2 = 1 z 2 \overline{z_2} = \frac{1}{z_2} and z 3 = 1 z 3 \overline{z_3} = \frac{1}{z_3}

\therefore 1 z 1 + 1 z 2 + 1 z 3 = 1 \left|\frac{1}{z_1}+\frac{1}{z_2}+\frac{1}{z_3}\right| = 1 becomes

z 1 + z 2 + z 3 = 1 \left|\overline{z_1}+\overline{z_2}+\overline{z_3}\right| = 1

By using properties of conjugate for a complex number , we get

z 1 + z 2 + z 3 = 1 \left|\overline{z_1+z_2+z_3}\right| = 1

Now by property of modulus of complex numbers ,

z = z \left|z\right| = \left|\overline{z}\right|

Hence , z 1 + z 2 + z 3 = 1 \left|z_1+z_2+z_3\right| = 1

NOTE : z \overline{z} is conjugate of z z

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