Consider 2 numbers and which are chosen at random from the set without replacement . If the probablity that is divisible by 3 can be written of the form
where and , find
If you feel that the probability cannot be expressed in this form then type 22 as your answer.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
The entire set can be split up into 3 sets of numbers of the form 3 m + 1 , 3 m + 2 , 3 m ,Three numbers can be chosen in ( 2 3 n ) ways. Also for sum of the cubes of the nos. To be divisivle by three either the numbers must be chosen from the third set o r one from set1 a n d the other from set 2. This can be done in ( 1 n ) 2 + ( 2 n ) ways. Therefore the required probability is ( 2 3 n ) ( 1 n ) 2 + ( 2 n ) which simplifies to 1/3. Comparing we get a=0, b=0 and c=1. Hence the answer is 0.