J. Addition strikes back
Level
2
2 + t2 = e4xp
5a + 7st = e12
12.c3 + 3o21 = 44m4
12/n3/4 + 43721 = 5555
s12n3j405 + 6o7s8n9 = 19134
2013 + 1234567 = ?
The answer is 1238594.
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1 solution
It is definitely NOT as simple as it seems. Note that random characters (including the full stop on third equation) are everywhere. Let's remove them. Now everything looks cleaner and is correct EXCEPT the fourth equation, which has an extra 7 and the fifth, which has an extra 0. Taking them off as well and then recreate the text (and the numbers removed) in the order gives
texpaste.com/n/7snj0osn
A link? Let's go there only to find out the note there. From there we see that we need to add 2014 to our answer so the correct answer is 2 0 1 3 + 1 2 3 4 5 6 7 + 2 0 1 4 = 1 2 3 8 5 9 4 .