r = 1 ∑ ∞ e π r 2 1 = 2 1 ( Γ ( a b ) π a 1 − 1 )
Given a and b are coprime positive integers, find a + b .
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thats great ......how did you learn all this.......... stuff thats awesome!!!!!
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Whenever I stumble upon such problem, I try to learn the concepts in my free time via Brilliant wiki, wikipedia and wolframmathworld. Though they are stuff mainly from pure mathematics and I'm preparing for JEE so I do not believe I have any better practice in this field, however, enough to tackle such direct problems with some thorough self-reading.
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One of the Jacobi theta functions gives us the identity
ϑ ( z ; τ ) = 1 + 2 n = 1 ∑ ∞ ( e π i τ ) n 2 cos ( 2 π n z )
Setting n = r , z = 0 and τ = i , we get
ϑ ( 0 ; i ) = 1 + 2 r = 1 ∑ ∞ ( e − π ) r 2 ⟹ r = 1 ∑ ∞ e π r 2 1 = 2 1 [ ϑ ( 0 ; i ) − 1 ]
The explicit value of ϑ ( 0 ; i ) is given by
φ ( e − π ) = ϑ ( 0 ; i ) = Γ ( 4 3 ) 4 π
Hence
r = 1 ∑ ∞ e π r 2 1 = 2 1 [ Γ ( 4 3 ) π 4 1 − 1 ]
So, a + b = 4 + 3 = 7 .