Jam Shock Speed

On a highway, there are 100 cars per kilometer and the cars are all moving at 100 km/hr 100 \text{ km/hr} . One car notices something and slams on its breaks, slowing down to 50 km/hr 50 \text{ km/hr} and halving the distance between itself and the car behind it.

How quickly does the shock wave generated move relative to the ground (in km/hr \text{ km/hr} )?

Give your answer to 3 decimal places.


The answer is 0.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Adam Strandberg
Mar 10, 2016

The velocity v L v_L before the shock is 100 km/hr, and the velocity v R v_R after the shock is 50 km/hr. The density after the shock is twice the density before the shock (since the distance between cars is halved) so k R = 200 k_R = 200 cars/km and k L = 100 k_L = 100 cars/km.

v w = q R q L k R k L v_w = \frac{q_R - q_L}{k_R - k_L} v w = ( 200 50 ) ( 100 100 ) 200 100 = 0 v_w = \frac{(200*50) - (100*100)}{200 - 100} = 0

Note: relative to the ground, the shock moves at 0 km/hr. But for all the cars moving at 100 km/hr, that means that the shock is coming towards them at 100 km/hr.

I feel like there should be a mention of the length of a car, as the faster we go the shorter our following time usually is.

Jerry McKenzie - 4 years ago
Mo Sh
Mar 10, 2016

The apparent backwards motion of the shockwave is exactly cancelled by the cars ground-relative velocity, giving an overall velocity of 0m/s.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...