Jed & his oranges

Let $\theta$ be the number of oranges Jed bought initially. After selling them, he now has $(1 - \frac{3}{5}) \times \theta \Rightarrow \frac{2}{5} \theta$ oranges. After throwing the bad ones away, he would have $(1 - \frac{1}{4} ) \times \frac{2}{5} \theta \Rightarrow \frac{3}{10} \theta$ oranges. Because $\frac{3}{10} \theta = 24$ , then $\theta = \boxed{80. \;}$

PS: I really loved solving this problem, Callum. Keep up the good work!

(2/5) * (3/4) * x= 24

So x=80

First, we consider the total of orange was purchased by jed is x. From the questions, we know that jed sell $\frac{3}{5}x$ and it means the remaining amount of orange is $x - \frac{3}{5}x = \frac{2}{5}x$ after that, jed throw a quarter of the remaining amount of orange, so now the remaining amount of oranges is $\frac{2}{5}x \times \frac{3}{4}= \frac{3}{10}x$ that equal to 24 oranges $\frac{3}{10}x = 24$ $3x=240$ $x=80$ therefore the totals of the orange that was purchased by jed is 80

We are told that at the end of the process Jed has 24 oranges - after selling three fifths of the original oranges and throwing away a further quarter of the remaining oranges. Answering this question is as simple as doing these fractions backwards.

Jed throws away one quarter of his oranges, leaving him with 24 left over. This means that 24 oranges is equivalent to three quarters of his left over oranges.

To find four quarters of the oranges that he didn't sell, we need to divide 24 by three to find one quarter, and multiply this by four to get four quarters:

$\frac{24}{3} = 8$ $8 \times 4 =32$

So now we know that the oranges Jed didn't sell total to 32. Now, we know Jed originally sold three fifths of his oranges, so 32 oranges must be worth the left over two fifths. To work out the original quantity of oranges, we just need to find one fifth and multiply this by five:

$\frac{32}{2} = 16$ $16 \times 5 = \boxed{80}$

And there we have it!

let 1 - the whole representation of the oranges that Jed bought

$1 - \frac{3}{5} = \frac{2}{5}$ (part of the oranges that are left)

$\frac{2}{5}\times\frac{3}{4} = \frac{3}{10}$ (part of the oranges that are good)

$\frac{24}{\frac{3}{10}} = 80$ (total number of oranges that Jed brought)

Since he sold $\frac{3}{5}$ of the oranges, he now has left $\frac{2}{5}$ of them.

Out of those, $\frac{1}{4}$ are bad, that means $\frac{3}{4}$ are good.

So he has $\frac{3}{4} \times \frac{2}{5}$ good oranges = $\frac{3}{10}$ good oranges.

Therefore, $\frac{3}{10} \times (total oranges) = 24 good oranges$ .

Hence, total oranges = $\boxed{80}$ .

That's the answer!

let 'x' be the total no. of oranges...... out these boy has sold 3/5(x) oranges....now he got ony 2/5(x) of oranges

out of these 2/5(x), 1/4 were bad so......so he throws those 1/4th oranges which he was left with after selling 3/5(x) oranges so now he got, 2/5(x)-(2/5(x) x1/4)=3/10 (x) 3/10 (x)=24 so x=80

The answer is 80. Simple exclusion method is used to solve it.

just assum that the total orange si bought as X.. that mean.. X - 3/5X - 1/4(X - 3/5X) = 24

3/5X = 3/5 he sold from total orange he bought ( X ) and 1/4 ( X - 3/5X) from he threw away 1/4 from what he had left (after he sold 3/5 X)

so, it's will make 2/5 X - 2/20 X = 24

X = 80

let x be the no. of oranges Jed bought

x - (3/5)x - (1/4)(x - (3/5)x) = 24

x = 80

Let's assume there are $x$ oranges.

$x - \frac {3}{5}x - \frac {2}{5}.\frac {1}{4}x = 24$

$x - \frac{3}{5}x - \frac{1}{10}x = 24$

$x (1 - \frac{3}{5} - \frac{1}{10}) = 20$

$x=80$

let 'x' be the initial oranges,3^5 were sold remaining were 2^5 out of these 1^4 were thrown away remaining were 2x/5-1/4(2x/5) i.e 3x/10=24 x=80

x-3/5x=2/5x=2/5x-2/20x=6/20x=24, then x =80

let "x" be the no of oranges he buy, he sold 3/5 of oranges from total. x-3X/5 = 2X/5. in remaining oranges 1/4 are bad.
2X/5*1/4= 2X/20= 1X/20.
remaining =2x/5-1x/10=3x/10.
which are equal to 24 oranges.
3x/10=24 ==x=240/3 =80

80 ORANGES

We say that x is the oranges that Jed bought. so: \frac{3} {5} x + \frac{1} {4} (x - \frac{3} {5} x) + 24 = x we solve the equation and it gaves us x = 80

total orange= (3/5)x+(2/5)x

2/5 of total orange = remaining orange with bad orange(1/4 of them)

2/5*1/4=.1

remaining is 24 this is 1-(3/5-.1)=1-.7=0.3 orange

24 oranges is .30 or 30 percent of total which is= 24/.30=80 oranges

Number of the oranges Jed bought = (24 * 4/3) * (5/2) = 80.

SInce he sells 3/5 he has 2/5 left. Of this 2/5, 1/4 are bad so he keeps 3/4 of the 2/5. 3/4 multiplied to 2/5 equals 3/10 which is equals to his 24 oranges.3/10x equals 24, therefore x=80