JEE-Advanced 2015 (19.B/40)

Calculus Level 3

f ( x ) = { 3 a x 2 2 , x < 1 b x + a 2 , x 1 f(x)=\begin{cases} -3ax^2-2 \ \ , \quad x<1 \\ bx+a^2 \ \quad \ \ , \quad x \geq 1 \end{cases} Let a a and b b be real numbers such that the above function f ( x ) f(x) is differentiable for all real x x , then find the possible value(s) of a a . \[\begin{array}{} (1) \, 1 \quad \quad \quad \quad \quad \quad \quad \quad & (2) \, 2 \\ (3) \, 3 & (4) \, 4 \end{array}\]
Note :

  • Submit your answer as the increasing order of the serial numbers of all the correct options.

  • For eg, if your answer is ( 1 ) , ( 2 ) (1),(2) , then submit 12 as the correct answer, if your answer is ( 2 ) , ( 3 ) , ( 4 ) (2),(3),(4) , then submit 234 as the correct answer.


The answer is 12.

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