JEE-Advanced 2015 (19.D/40)

Algebra Level 4

Let the harmonic mean of two positive real numbers a a and b b be 4. If q q is a positive real number such that a , 5 , q , b a, \ 5, \ q, \ b is an arithmetic progression, then find the value(s) of q a |q-a| . \[\begin{array}{} (1) \, 1 \quad \quad \quad \quad \quad \quad \quad \quad & (2) \, 2 \\ (3) \, 3 & (4) \, 5 \end{array}\] Note:

  • Submit your answer as the increasing order of the serial numbers of all the correct options.

  • For eg, if your answer is ( 1 ) , ( 2 ) (1),(2) , then submit 12 as the correct answer, if your answer is ( 2 ) , ( 3 ) , ( 4 ) (2),(3),(4) , then submit 234 as the correct answer.


The answer is 24.

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1 solution

Mayank Jha
Jun 20, 2015

Since the HM of a,b is 4 so we first find the relationship between a&b as 1/a+1/b=1/2.Then since a,5,b,q are in AP of common difference 5-a we express b in terms of a and substitute it in first equation. We get a=6,2.5and correspondent values of q. Then find the difference and then it's absolute value and enjoy😂the fact that jee question was sooo easy. I am in class10 right now and am able to solve it in first attempt.

Same here me also in 10th but I could have solved it in 8th or 9th also. Cheers we are on the right path.

Kushagra Sahni - 5 years, 11 months ago

humbleness of your knowledge is the right path

Aditya Gahlawat - 4 years, 9 months ago

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