If I = ∫ sin x sin ( 2 x + α ) d x for 0 < α < 2 π and f ( x ) = lo g ∣ ∣ ∣ cot x + cot α + cot 2 x − csc 2 α ∣ ∣ ∣ , then find I .
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I can be determined in a closed form, but let's just observe and plug in x = π / 4 and then we see that derivative of I gives a real number where f(x) doesn't.