Find the maximum number of electrons in Aluminium for which [(l*m)/n] = 0. where l, m, n are quantum numbers. N.B:- [..] is not GIF.
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For Al: 1s2 2s2 2p6 3s2 3p1.
For n=1, l=0 and m=0 a maximum of 2 electron.
For n=2, l=0 and m=0 a maximum of 2 electron.
For n=2, l=1 and m=0 a maximum of 2 electron.
For n=3, l=0 and m=0 a maximum of 2 electron.
For n=3, l=1 and m=0 a maximum of 1 electron.