JEE Coordinate (6)!

Geometry Level 4

The slopes of three sides of a triangle are -1 , -2 and 3 .

If the orthocenter of this triangle is the origin, and the locus of the centroid of this triangle can be expressed as x y = m n \dfrac xy = \dfrac mn , where m m and n n are coprime positive integers, find m n m-n .


This is a part of my set Practice for JEE 2017!
2 7 3 6 1 5 8 4

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1 solution

Sumanth R Hegde
Jan 11, 2017

Consider the vertices of the triangle to be

( x 1 , y 1 ) , ( x 2 , y 2 ) , ( x 3 , y 3 ) (x_1, y_1) ,(x_2,y_2) , (x_3,y_3 )

Now the slopes of the sides are known.Using this we will get a few equations in the unknowns .

Now , altitude drawn from a vertex passes through the origin.Using this we will get a few more equations.Solve these to express all variables in terms of only one variable.

Co ordinates of centroid are ( x 1 + x 2 + x 3 3 , y 1 + y 2 + y 3 3 ) ( \frac{x_1 + x_2 + x_3}{3} , \frac{y_1 + y _2 + y_3}{3}) . Take the ratio of x x and y y coordinates .

We will get m n = 9 2 \large \color{#D61F06}{\frac {m}{n} = \frac{9}{2}}

The answer is 7 \color{#3D99F6}{\boxed{7}}

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