JEE Main 2016 (5)

If the equation $z^{2}+z+\omega=0$ has purely imaginary root and $ω$ lies on the circle $|z|=1$ and $1+\omega+\omega'=\sqrt{A}$ . Find $A$

$ω'$ implies the complex conjugate of $\omega$ .

Try my set JEE Main 2016 .