JEE-Mains 2014 (5/30)

Algebra Level 4

\[\displaystyle \left| \begin{array}{} 3 & 1+f(1) & 1+f(2) \\ 1+f(1) & 1+f(2) & 1+f(3) \\ 1+f(2) & 1+f(3) & 1+f(4) \end{array} \right|= k(1-\alpha)^2(1-\beta)^2(\alpha-\beta)^2\]
If α , β ≠ 0 \alpha,\beta \neq 0 , and f ( n ) = α n + β n f(n)=\alpha^n+\beta^n , then k k is equal to :

1 α β \frac{1}{\alpha\beta} 1 -1 α β \alpha\beta

Sandeep Bhardwaj by Sandeep Bhardwaj , 28, India

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1 solution

Hitesh Yadav
Aug 27, 2020

(This is not a solution to the probem) . Sir I think there is some problem with the latex in the question which makes it hard to read and understand.

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