JEE Mains 2013 Question No. 4 (Chemistry)

Chemistry Level 1

The molarity of a solution obtained by mixing 750 mL 750 \text{ mL} of 0.5 M 0.5\text{ M} hydrochloric acid with 250 mL 250\text{ mL} of 2 M 2 \text{ M} hydrochloric acid is X X . Find the value of 40 X 40X .


The answer is 35.

View wiki
Hrishik Mukherjee by Hrishik Mukherjee , 21, India

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Vaibhav Prasad
Apr 9, 2015

M 1 V 1 + M 2 V 2 = M 3 ( V 1 + V 2 ) \huge {M_1V_1+M_2V_2 = M_3(V_1+V_2)}

14 Helpful 0 Interesting 0 Brilliant 0 Confused

(m1v1+m2v2)/(v1+v2)=m3 0.5 750+2 250/1000=0.875; 0.875*4

TISHA SOUMYA - 4 years ago

Log in to reply

0.875M is the right answer

Piyush Upadhyay - 3 years, 10 months ago

Wrong answer .875M is correct

Anurag Gaurav - 3 years, 10 months ago

35 is the correct answer thank you

Aditya Karkera - 2 years, 10 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...