Let and are two sets containing four and two elements respectively. Then the number of subsets of the set , each having at least three elements is:
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The no. Of ordered pairs in the set A×B is 4 × 2 = 8 So no of total subsets of A×B is 2 8 = 2 5 6
We have to subtract the subsets which have less than 3 elements from the total no. Of subsets 2 5 6 − 8 C 0 − 8 C 1 − 8 C 2 = 2 5 6 − 1 − 8 − 2 8 = 2 1 9