JEE-Mains 2015 (13/30)

Calculus Level 3

Given : lim x 0 [ 1 + f ( x ) x 2 ] = 3 \text{ Given : } \displaystyle \lim_{x \to 0} \left[ 1+\dfrac{f(x)}{x^2} \right]=3
If f ( x ) f(x) be a polynomial of degree four having extreme values at x = 1 x=1 and x = 2 x=2 , then f ( 2 ) f(2) is equal to :

-4 4 -8 0

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