JEE Mains Indefinite Integration 1

Calculus Level 2

Calculate ( sin x cos x cos 2 x cos 4 x cos 8 x cos 16 x ) d x \displaystyle\int (\sin x\cos x\cos 2x\cos 4x\cos 8x\cos 16x)dx

This problem is a part of My Picks for JEE Mains 1
cos 32 x 1024 + C -\dfrac{\cos 32x}{1024}+C cos 32 x 1096 + C \dfrac{\cos 32x}{1096}+C sin 16 x 1024 + C \dfrac{\sin 16x}{1024}+C cos 32 x 1096 + C -\dfrac{\cos 32x}{1096}+C

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1 solution

Himanshu Aswani
Mar 26, 2015

keep on multiply and divide by 2

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