JEE Novice - (33)

Algebra Level 1

( x a x b ) a 2 + a b + b 2 . ( x b x c ) b 2 + b c + c 2 . ( x c x a ) c 2 + c a + a 2 = ? \Large \left(\dfrac{x^a}{x^b}\right)^{a^2+ab+b^2} . \left(\dfrac{x^b}{x^c}\right)^{b^2+bc+c^2} . \left(\dfrac{x^c}{x^a}\right)^{c^2+ca+a^2} \ = \ ?


This question is a part of JEE Novices .


The answer is 1.

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1 solution

Rohit Ner
May 29, 2015

( x a x b ) a 2 + a b + b 2 . ( x b x c ) b 2 + b c + c 2 . ( x c x a ) c 2 + c a + a 2 \Large \left(\dfrac{x^a}{x^b}\right)^{a^2+ab+b^2} . \left(\dfrac{x^b}{x^c}\right)^{b^2+bc+c^2} . \left(\dfrac{x^c}{x^a}\right)^{c^2+ca+a^2} = x ( a b ) ( a 2 + a b + b 2 ) . x ( b c ) ( b 2 + b c + c 2 ) . x ( c a ) ( c 2 + a c + a 2 ) \Large = { x }^{ \left( a-b \right) \left( { a }^{ 2 }+ab+{ b }^{ 2 } \right) }.{ x }^{ \left( b-c \right) \left( { b }^{ 2 }+bc+{ c }^{ 2 } \right) }.{ x }^{ \left( c-a \right) \left( { c }^{ 2 }+ac+{ a }^{ 2 } \right) } = x a 3 b 3 . x b 3 c 3 . x c 3 a 3 \Large = { x }^{ { a }^{ 3 }-{ b }^{ 3 } }.{ x }^{ { b }^{ 3 }-{ c }^{ 3 } }.{ x }^{ { c }^{ 3 }-{ a }^{ 3 } } = x a 3 b 3 + b 3 c 3 + c 3 a 3 \Large = { x }^{ { a }^{ 3 }-{ b }^{ 3 }+{ b }^{ 3 }-{ c }^{ 3 }+{ c }^{ 3 }-{ a }^{ 3 } } = x 0 \Large = { x }^{ 0 } = 1 \Huge =\boxed { 1 }

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