JEE Probability

If A 1 , A 2 , A 3 . . . . . A 1006 A_{1},A_{2},A_{3}.....A_{1006} be independent events such that P ( A i ) = 1 2 i ( i = 1 , 2 , 3....1006 ) P(A_{i})=\frac{1}{2i}(i=1,2,3....1006) and probability that none of the events occurs be α ! 2 α ( β ! ) 2 \frac{\alpha!}{2^{\alpha}(\beta!)^{2}} , then

A ) A) - β \beta is of form 4 k + 2 4k+2 where k k is a positive integer.

B ) B) - α = 2 β \alpha=2\beta

C ) C) - β \beta is a composite number

D ) D) - α \alpha is of form 4 k 4k where where k k is a positive integer.

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A B D ABD B D BD A B C D ABCD A C AC B C BC A C D ACD A B AB B C D BCD

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1 solution

Mvs Saketh
Mar 7, 2015

Yes,

the probability that no event should occur is

1 1006 ( 1 1 2 i ) \prod_{1}^{1006} (1-\frac {1}{2i})

which can be rearranged as

2012 ! 2 2012 ( 1006 ! ) 2 \frac {2012!}{2^{2012}(1006!)^{2}}

hence ABCD

Nice solution and thanx,

Tanishq Varshney - 6 years, 3 months ago

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I guess I was late as usual ! Sorry abt that .

A Former Brilliant Member - 6 years, 3 months ago

Did the same :)

A Former Brilliant Member - 6 years, 3 months ago

yay

it should be alg imo

math man - 6 years, 3 months ago

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