JEEometry

Geometry Level 4

The product of the length of the perpendiculars drawn from the foci to any tangent to the ellipse x 2 1729 + y 2 1728 = 1 \frac{x^{2}}{1729}+\frac{y^{2}}{1728}=1 is equal to

none of these 12 1729 1728

Shivam Jadhav by Shivam Jadhav , 22, India

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1 solution

Rahul Singh
Apr 8, 2017

We can use the property of ellipse that the product of length of perpendiculars drawn from foci to any tangent is b^2....hence here b^2 = 1728

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