A typical jigsaw puzzle has 4 corner pieces, a number of edge pieces, and the rest interior pieces. (See the drawing above.)
A certain jigsaw puzzle has 50% more pieces horizontally than vertically, and 13.0% of the pieces are edges.
Calculate the horizontal dimension of the puzzle.
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Let x , y be the horizontal and vertical dimensions of the puzzle. Then we have
total number of pieces: N = x y ;
interior pieces: I = ( x − 2 ) ( y − 2 ) ;
edge pieces: E = N − I − 4 = x y − ( x − 2 ) ( y − 2 ) − 4 = 2 ( x + y ) − 8 .
We are told that x = 1 2 1 y E = 0 . 1 3 ⋅ N , which gives the following equation for y : 0 . 1 3 ⋅ 1 2 1 y ⋅ y = 2 ( 1 2 1 y + y ) − 8 0 . 1 9 5 y 2 = 5 y − 8 0 . 1 9 5 y 2 − 5 y + 8 = 0 . The solutions of this quadratic equation are y = 2 ⋅ 0 . 1 9 5 5 ± 5 2 − 4 ⋅ 0 . 1 9 5 ⋅ 8 = 0 . 3 9 5 ± 1 8 . 7 6 ≈ 2 3 . 9 3 or 1 . 7 1 . Clearly the latter solution makes no sense. We conclude that y = 2 4 , so that x = 3 6 .
Check: A 2 4 × 3 6 puzzle has
N = 2 4 ⋅ 3 6 = 8 6 4 pieces in total,
of which I = 2 2 ⋅ 3 4 = 7 4 8 interior pieces,
and E = 8 6 4 − 7 4 8 − 4 = 1 1 2 edge pieces,
so that the percentage of edge piece is E / N = 1 1 2 / 8 6 4 ≈ 1 2 . 9 6 % . .