John the Old Man

Let $x$ be the length of his life (in years). Then,

$x/4 + x/6 + x/2 + 6 = x,$

so

$\frac{3x+2x+6x+72}{12} = x.$

This gives $12x=11x+72,$ so $x=72.$

1/4 + 1/6 + 1/2 = 11/12 12/12 - 11/12 = 1/12 so 1/12 is 6 years thus 6 x 12 = 72

6 years = 1-(1/2 + 1/4 + 1/6) =1/12 of his life

6×12=72

18 x 4 = 72

I simplified all of the fractions into 12ths (as in 1/12 fragments) Then added the fractions together. 11/12ths left 6 as the value of 1/12th, so 6x12 was his age.

The easier solution is simply to assume that he was legally grown up at 18....and multiply it by 4. The solution is correct. John spent quite a while in college apparently.

(1/4 + 1/6 + 1/2) x +6 = x

x = 72

i like this problem because it's so easy so he spent 1/4 of his life then 1/6 then 1/2 the six years so we need to do this we take that x is his entire life
so 1/4 x + 1/6 x + 1/2 x = 11/12 x and there is 6 years left before he died so 1/12 x = 6 x=72

I just guessed on my first attempt, you can too.

Since he spend half of his life teaching 1/2 That means the other half is the rest = 1/4+1/6+6 years

so, x/4+x/6+6=x/2

x/4+x/6-x/2=-6 -x/12=-6

-x=-72 (-1)

x=72

6 years is the rest of his life aside from the portions mentioned. 6=x-x/6 -x/2 -x/4 = x/12 -> x=6(12)=72

People grow up to become adults. So i assumed that a fourth of his life was 18 years and hence his life was 72 years

x\4+x\6+x/2+6=x ; (3x+2x+6x+72)/12=x. Therefore, 11x+72=12x; 72=12x-11x; x=72.

Ok, I sum them all (not the 6 years) and I got 11/12. Now let me tell you something, one per 12 of John's life is his last time to live, and it said 6 years! So 6x12=72 years old.

X1/4+x1/6+x1/12+6=x 6=x-x11/12 6=x/12 X=72

Age = boy + student + teacher + retired a = 1/4 a + 1/6 a + 1/2 a + 6 Multiply by 12 to get rid of the denominators, results 12a = 3a + 2a + 6a + 12(6) 12a = 11a + 72 12a - 11a = 72 a = 72 is his age when he passed away.

It's very simple. Since 11/12 of his life are accounted for, and there are 6 years left, you can assume 6 years is 1/12 of John's life. So multiply 6 by 12.

The six years are the remaining fraction of his life. To find this add up all the other fractions as 12/24+6/24+4/24=22/24 So 6 =2/24 6*12 = 72

x/4+x/6+x/2+6=x x=72

I just solved it by adding the fractions, then using that portion to determine how old he was. 1/4+1/6+1/2=22/24. Which means 2/24 (1/12) of his life is 6 years. 12*6=72

The difference between his past life experience and his death age is 6,so he was 72 when he died

since (x/2) is half of his life

then (x/4 + x/6 + 6) = (x/2)

12 (x/4 + x/6 + 6) = 12 (x/2)

3 x + 2 x + 72 = 6 x

x = 72

Let's assume that his age was x.so he spent x/4 years in growing up,x/6 in college,x/2 as a teacher.here the equation goes (x/4+x/6+x/2+6)=x or,(3x+2x+6x+72) /12=x or,11x+72=12x. or,x=72

Let his total age be x.. Then acc. To given ques.. Equation is- x/4+x/6+x/2+6 = x Hence by solving the above equation we get x=72

1/4 + 1/6 + 1/2 = 11/12 1 - 11/12 = 1/12 Since 1/12 = 6 Then multiply 6 by 12, So,the answer is 72 year old.

1/4=3/12, 1/6=2/12, 1/2=6/12. 3/12+2/12+6/12=11/12. The remainder, 1/12 is equal to 6 years. 6·12=72 years.

X/2 + X/4 + X/6 + 6 = X This gives X = 72