Joseph invests $ 6000 for 3 years at 4.5% simple interest in Simple Bank. The interest is paid, by cheque, at the end of each year. Joseph also invests $ 6000 for 3 years at 4.2% compound interest in Compound Bank. Which bank pays Joseph the greater amount of total interest?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
The formula for simple interest is: F s = P + P × 1 0 0 R × t
The formula for compound interest (when interest is counted every year) is: F c = P ( 1 + 1 0 0 i ) t
In this case the present value is $ 6 0 0 0 , time is 3 years and interest of simple bank R = 4 . 5 % , interest of compound bank i = 4 . 2 % . Let's add all those numbers to both formulas and solve them:
1) F s = 6 0 0 0 + 6 0 0 0 × 1 0 0 4 . 5 × 3 = 6 8 1 0
2) F c = 6 0 0 0 ( 1 + 1 0 0 4 . 2 ) 3 ≈ 6 7 8 8 . 2
We can easily see now that: F s > F c .