Joseph the economist

Joseph invests $ 6000 for 3 years at 4.5% simple interest in Simple Bank. The interest is paid, by cheque, at the end of each year. Joseph also invests $ 6000 for 3 years at 4.2% compound interest in Compound Bank. Which bank pays Joseph the greater amount of total interest?

Not enough data Simple Bank Both pay the same amount of total interest Compound Bank

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2 solutions

Zyberg Nee
Apr 2, 2016

The formula for simple interest is: F s = P + P × R 100 × t F_s = P + P \times \frac{R}{100} \times t

  • F s F_s - Future value,
  • P P - Present value,
  • R R - The interest value per year,
  • t t - Time.

The formula for compound interest (when interest is counted every year) is: F c = P ( 1 + i 100 ) t F_c = P(1 + \frac{i}{100})^{t}

  • F c F_c - Future value,
  • P P - Present value,
  • i i - Nominal interest rate,
  • t t - Time.

In this case the present value is $ 6000 \$6000 , time is 3 3 years and interest of simple bank R = 4.5 % R = 4.5\% , interest of compound bank i = 4.2 % i = 4.2\% . Let's add all those numbers to both formulas and solve them:

1) F s = 6000 + 6000 × 4.5 100 × 3 = 6810 F_s = 6000 + 6000 \times \frac{4.5}{100} \times 3 = 6810

2) F c = 6000 ( 1 + 4.2 100 ) 3 6788.2 F_c = 6000(1 + \frac{4.2}{100})^3 ≈ 6788.2

We can easily see now that: F s > F c \boxed{F_s > F_c} .

Jase Jason
Mar 19, 2016

Too straightforward. 4.5% > 4.2%

Your answer may be right but your method is wrong. There is not much difference between 4.2% simple interest and 4.5% compound interest

Boss Agarwal - 2 years, 5 months ago

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