Journey of a Train!
One train travels cross country between 2 major Stations, A and B. Total distance between two major Station is 1742 km. Train do one round trip in a week from A to B and B to A.
- Train departs from Station A on Day 1 at 10.00 AM and reaches Station B at certain time on Day 2.
- Small Station C comes in between the journey which is 854.25 km away from Station A. Train reaches there at 10.45 PM on Day 1.
- Train starts return trip from Station B to A on Day 3 at 3.00 PM. While on return journey, train travels on average 1/4 higher speed than earlier trip.
You need to tell at what time train must be arriving on Station C on return journey.??
You may assume that average speed of the train throughout the journey remains the same.
You may round off all figures till 2 digits as well.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
1 solution
It seems simple problem, but it is not that easy. Lets calculate.
Firstly we need Average Speed of the train in trip of A to B. It is given than distance between A to C is 854.25 km. It is also given that train reaches to Station C at 10.45 PM on Day 1. So total time taken from Station A to C is 12 Hrs and 45 Minutes. We have to convert it in number figure, which will be 12.75. Now divide 854.25 by 12.75, we will get Average Speed of 67.00 km/hr.
Now we have to find new average speed. It is given that on return trip of B to A, train travels at 1/4 higher speed. So New Average Speed will be 67.00*125/100 = 83.75 km/hr.
Now find distance from B to C, which is 1742 km - 854.25 km = 887.75 km.
And finally we have to calculate hours require to travel from B to C, which will be 887.75/83.75 = 10.60 (in number). Don't forget to convert it back it into hours. Which will be 10 Hrs and (0.60*60/100) 36 Minutes.
Add 10 Hrs and 36 Minutes in 3.00 PM on Day 3. Which will give final answer of 1:36 AM Day 4.