Journey To The Center Of The Earth

In the Vernian adventure, A Journey to the Center of the Earth , Professor Lidenbrock finds a vast underground cavern several miles below the surface of the Earth.

Where does the Professor weigh more: in the underground cavern, or on the surface of the Earth?

Assumptions and Details

  • The Earth has a uniform density.
He weighs more in the underground cavern He weighs more on the surface of the Earth He weighs the same in both places

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2 solutions

Pranshu Gaba
Jun 8, 2016

We can treat Earth as a uniform solid sphere, made of many concentric shells. By Gauss' Law, the gravitational field at any point inside a uniform shell is zero.

  • When the professor stands on the surface of Earth, he experiences gravitational force due to all concentric shells.

  • When he descends to the cavern, only the concentric shells between him and the center of the Earth exert a force on him. The shells that are above him do not exert force on him, by Gauss' Law.

Thus, he weighs more on the surface of the Earth. _\square

Weight is a bad word to be used in this context because it can be understood as both mass or force.

Ibo Hai - 5 years ago

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It's not bad at all. Weight is always a force.

W = m g W=mg

Kenneth Choo - 4 years, 11 months ago
Sabbir Ahmed
Jun 7, 2016

At a particular depth the mass of earth is density 4/3 (22/7) (R-h)^3. Therfore the value of g is Gm/(R-h)^2. Therefore the value of g is density 4/3 (22/7) (R-h). So, the equation of g clearly shows that as depth increases the value of g decreases and hence weight of the person decreases with depth.

The mass of the earth doesn't decrease as you go down. The mass below you does decrease but the mass above you still pushes you upwards.

As you go down your weight upwards increases and your weight downwards decreases at exactly the same speed.

Peleg Tsadok - 5 years ago

You forgot to include the spin of earth with a decreasing radius.

TR4Zzer BOSS - 5 years ago

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