Jumping on the number line

A Bug is sitting on the origin of the number line. Each step he jumps 3 units or 5 units to the right. There is a mine at all integer points that are neither divisible by 3 nor 5, and Bug wants to avoid all those points. His house is at 120. How many ways can he jump back to his home?


The answer is 256.

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1 solution

L.C.M of 3 & 5 is 15. So bug has to cover 15 units(continuously) by taking one of the jumps i.e. either by jumps of 5 units or 3 units to avoid mines. Like it can cover 120 units at 8 stretches. Since in each stretch it has got 2 options to follow the required number of ways is 2^8 i.e. 256

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