Junior Serbian Math Olympiad 2016 2

Find the minimal number of natural positive divisors of the number 201 6 n 3 6 m |2016^{n}-36^{m}| , where n n and m m are positive integers .


The answer is 30.

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1 solution

Rishabh Tiwari
May 22, 2016

We must have the given no. As smallest possible...hence we look out for

2016 - (36)^2 = 720, which has 30 factors. I did it by hit & trial so I request someone to please post a reasonable solution! Thank you!

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