In the right triangle above, a height is drawn to the hypotenuse. Find x + y + z .
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now i look at my solution... and found it over complicating...
please explain how can you tell that , 12/15=z/9
The angle between y and 12 is inside two triangles: the triangle with sides z, y and 12 and the triangle with sides 9, 12 and (x+y). Along with the right angle their third angles must also be equal. So the triangles are similar and the ratios of their sides can be used to find z.
The triangles are similar if they have the same shape, but can be different sizes. The 1 2 side in the smaller triangle is similar with the 1 5 in the bigger triangle. Then so do the z side and 9 side.
by equalizing the area equations i.e 1/2 b h here take h=z and b=hypo. then h=9 and b=12
.Similar triangles. Opposite/Hypotenuse (smaller)=Opp/Hyp (bigger)
He just computed the area of the triangle without the division by two
find x, y, and Z using Pythogoras theorem as the remaining angles are 45 Degree x+y+z=22.21 we get
which angle is 45 Degree here ??
Pythagorean Theorem: x + y = 1 5
Area of whole figure = 2 1 ⋅ 9 ⋅ 1 2 = 5 4 .
However we can calculate the area another way, which is
2 1 ⋅ ( x + y ) ⋅ z
But the area is 5 4 , so
2 1 ⋅ ( x + y ) ⋅ z = 5 4
Subsituting the value of x + y and solving the equation, we will get z = 7 . 2
So, x + y + z = 2 2 . 2
Elegant!
best answer
Cool!
I'm used to brute force method since I'm lacking knowledge for shortcuts in these matters. However, this is simply mathematics that happens to be possible to solve.
By Pythagoras Theorem for all three triangles,
x + y = 8 1 + 1 4 4 = 1 5 − − − ( 1 )
8 1 = x 2 + z 2 , left triangle
1 4 4 = y z + z 2 , right triangle
hence,
x = 8 1 − z 2 − − − ( 2 )
y = 1 4 4 − z 2 − − − ( 3 )
by substituting (2) and (3) into (1),
8 1 − z 2 + 1 4 4 − z 2 = 1 5
8 1 − z 2 = 1 5 − 1 4 4 − z 2
Square both sides, and we get,
8 1 − z 2 = 2 2 5 + 1 4 4 − z 2 − 3 0 1 4 4 − z 2
1 4 4 − z 2 = 9 . 6
z 2 = 1 4 4 − 9 . 6 2
z = 1 4 4 − 9 . 6 2
z = 7 . 2
Hence,
x + y + z = 2 2 . 2
I actually have thought of using ratio, but I didn't know how to use it appropriately
the best method for doing this question is by similarity or using area of triangle formula
I never thought of the triangle formula though. I tried similarity, but maybe I used the wrong comparison to choose, that is why I never got the answer.
Those are the stpes {y2 + z2 = 122 : Pythagora's theorem x2 + z2 = 92 : Pythagora's theorem (y + x)2 = 122 + 92 : Pythagora's theorem x + y = 15 : Solve equation C by extracting the square root y2 - x2 = 63 : subtracting equations A and B (y - x)(y + x) = 63 : factoring the left term of equation E. y - x = 21/5 x = 2 7 / 5 , y = 4 8 / 5 and z = 3 6 / 5 and then add them to get 22.2
An easier approach is that x + y = 9 2 + 1 2 2 = 1 5 and z = 1 5 9 × 1 2 = 7 . 2 .
thanks
following three equations can be derived from the fig. x^2+z^2=81; y^2+z^2=144 and x+y=15
solving these equations we get x=5.4, y=9.6 and z=7.2
adding these we get 22.2
X+y=13 Z2+(13-x)2=144 X2+z2=81 Solve this and x comes 8.024 So x+y+z=13+8.024=21.024.. How come its 22.1 then??
nice question...
x+y=15, then take tan of both angles and equate them to get 12z/9=y and 9z/12=x, now add both to get x+y=4z/3+3z/4, substitute for x+y and get z=7.2
x2+z2=81,y2+z2=144 eq 1 then 81-x2=144-y2 y2-x2=63 (y+x)(y-x)=(8+1)(8-1) then y=8,x=1 put x or y value in eq 1 z2=81-1=80 z=8.944 we have x,y,z values x+y+z=8+1+8.944=17.944
By Pythagoras's theorem (x+y)= sqrt(81+144) = 15. Also, area of triangle = 9 12/2 =54 = (x+y) z/2 = 15z/2. Thus, z=7.2. Thus, x+y+z= 15+7.2 = 22.2.
It is a problem based on right angle altitude theorem first of all we get the sum of the (x+y) by pythagoras theorem Then by right angle altitude theorem we get 12^2=15y 9^2=15x z^2=xy
9x12=108
then z x (X+Y)=108
then X+Y=108/z
and 9²+12²=(X+Y)²=225 then X+Y=15
15=108/z so Z=108/15=7.2
X+Y+Z=15+7.2=22.2
once we get x+y=15 using Pythagoras theorem .. we can equate the two formula's of area which are [0.5 base height]={[s (s-a) (s-b)*(s-c)]^0.5}... using this we can get the height(z).
Equating the Area of the right angled triangle through base (x+y) with Area of the right angled triangle through base 9 ...
1/2 ( 9 * 12 ) = 1/2 ( z * 15 ) this implies z = 7.2
Using Pythagoras Theorem, (x+y)^2 = 9^2 + 12^2 this implies (x+y) = 15
Hence, x+y+z = 15 + 7.2 = 22.2
in the given fig x+y=15 x^2+z^2=81 144=z^2+y^2 equating z y^2-x^2=63 from 1st equation (15-x)^2-x^2=63 x=5.4 81=(5.4)^2+z^2 z=7.2 y=15-5.4 y=9.6 x+y+z=22.2
All the angles of all the triangles are easily know,they are 53 degree and 37 degree,hence by applying cos and sin we can easily find the values of x,y,z
i did it using the following: area of triangle=9X12/2=54 also by pythagoras, x+y=15 also area of triangle=1/2XzX15=54 z=7.2 sum=22.2
by applying Puthagoras theorem then BC = sqrt(AB^2+AC^2) == sqrt(9^2+12^2) = 15. We have AH = AB AC/BC = 9 12/15 = 7.2. Then x + y + z = BC + AH = 22.2
Applying Pythagorean Theorem (a^2+b^2=c^2):
(9^2) + (12^2) = (x+y)^2
225 = (x+y)^2
15 = x+y
Getting the equation for each smaller triangle:
(9^2) = *[(15-y)^2] + (z^2)
(12^2) = *[(15-x)^2] + (z^2)
*Keep in mind that x+y = 15, and x = 15-y, y = 15-x
---> Notice that both equations contain a (z^2) <---
Rewrite each equation so that each will be equal to (z^2):
(z^2) = (9^2) - [(15-y)^2]
(z^2) = (12^2) - [(15-x)^2]
Rewrite into one equation:
(9^2) - [(15-y)^2] = (12^2) - [(15-x)^2]
Solve:
[(15-x)^2] - [(15-y)^2] = (12^2) - (9^2)
[225-30x+(x^2)]-[225-30y+(y^2)] = 144 - 81
-30x + (x^2) + 30y - (y^2) = 63
[(x^2)-(y^2)] - (30x+30y) = 63
*(x+y)(x-y) - 30(x-y) = 63
*Remember that x+y = 15
15(x-y) - 30(x-y) = 63
(x-y)(15-30) = 63
-15(x-y) = 63
x-y = -4.2
Now we have two equations:
x+y = 15 & x-y = -4.2
Solve:
x+y = 15
x-y = -4.2
2x = 10.8
x = 5.4
(9^2) = (5.4^2) + (z^2)
81-29.16 = z^2
51.84 = z^2
7.2 = z
x+y+z = 15 + 7.2 = 22.2
Final Answer: 22.2
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x + y = 9 2 + 1 2 2
x + y = 8 1 + 1 4 4
x + y = 2 2 5
x + y = 1 5
Then..
1 5 1 2 = 9 z
z = 7 . 2
So..
x + y + z = 1 5 + 7 . 2
x + y + z = 2 2 . 2