Just a test

Calculus Level 3

This problem is just a test. I have noticed that some new problems aren't actually "new." Tomorrow (9/29), I will edit this problem's topic in order to test the hypothesis:

If a problem is edited at all, then the community algorithm will count it as new.

To discuss this issue/hypothesis and see the results of this "experiment," click here .

Since this needs to be a problem...

lim ⁡ x → − 3 2 x 3 + 2 x 2 − 11 x + 3 x + 3 = ? \displaystyle\lim_{x\rightarrow -3}\frac{2x^3+2x^2-11x+3}{x+3}=?


The answer is 31.

Blan Morrison by Blan Morrison , 18, USA

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1 solution

X X
Sep 29, 2018

Use L'Hopital Rule, the limit will become lim ⁡ x → − 3 ( 6 x 2 + 4 x − 11 ) = 54 − 12 − 11 = 31 \displaystyle\lim_{x\to-3}(6x^2+4x-11)=54-12-11=31

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