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Geometry Level 3

cot 3 2 tan 8 6 tan 2 3 tan 1 6 tan 6 7 tan 4 tan 7 4 tan 3 2 \cot { 32^\circ } \tan { 86^\circ } \tan { 23^\circ } \tan { 16^\circ } \tan { 67^\circ } \tan { 4^\circ } \tan { 74^\circ } \tan { 32^\circ } Find the value of the trigonometric expression above.

3 \sqrt { 3 } 1 1 Undefined 1 3 \frac { 1 }{ \sqrt { 3 } }

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1 solution

Chew-Seong Cheong
Jan 17, 2017

P = cot 3 2 tan 8 6 tan 2 3 tan 1 6 tan 6 7 tan 4 tan 7 4 tan 3 2 As tan θ = cot ( 9 0 θ ) = cot 3 2 cot 4 cot 6 7 cot 7 4 tan 6 7 tan 4 tan 7 4 tan 3 2 Note that cot θ = 1 tan θ = tan 6 7 tan 4 tan 7 4 tan 3 2 tan 3 2 tan 4 tan 6 7 tan 7 4 = 1 \begin{aligned} P & = \cot 32^\circ {\color{#3D99F6} \tan 86^\circ \tan 23^\circ \tan 16^\circ} \tan 67^\circ \tan 4^\circ \tan 74^\circ \tan 32^\circ & \small \color{#3D99F6} \text{As } \tan \theta = \cot (90^\circ - \theta) \\ & = \cot 32^\circ {\color{#3D99F6} \cot 4^\circ \cot 67^\circ \cot 74^\circ} \tan 67^\circ \tan 4^\circ \tan 74^\circ \tan 32^\circ & \small \color{#3D99F6} \text{Note that } \cot \theta = \frac 1{\tan \theta} \\ & = \frac {\tan 67^\circ \tan 4^\circ \tan 74^\circ \tan 32^\circ}{\color{#3D99F6} \tan 32^\circ \tan 4^\circ \tan 67^\circ \tan 74^\circ} \\ & = \boxed{1} \end{aligned}

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