Just AP 3

Algebra Level pending

Let a n a_n be a finite arithmetic progression such that the first term is a negative number and for 2 k 1 n 2k-1 \leq n , the k th k^\text{th} term of this progression is equal to 0. Find the sum of the first 2 k 1 2k-1 terms of this progression.


The answer is 0.

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2 solutions

Ashish Menon
Aug 7, 2016

The first term is a negative number provea that the common difference is not equal to 0.
Now, we see that the number of terms are odd (2k - 1). And we are also given that the k th k^{\text{th}} term (which is the middle term) is 0. So, there are (k-2) terms on either side of 0 with the the same common difference which means that the terms equidistant from 0 are equal in magnitude and opposite in sign. So, adding them, they cancel out each other and gives the sum 0 \color{#3D99F6}{\boxed{0}} .

Ku John
Aug 6, 2016

there is just zero sums

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