If the 2 nd , 5 th and 9 th of a non-constant arithmetic progression follows an geometric progression , what is the common ratio of this geometric progression?
Give your answer to 2 decimal places.
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T e r m 2 = a+d
T e r m 5 = a+4d
T e r m 9 = a+8d
As, T e r m 2 , T e r m 5 and T e r m 9 are in GP:
( a + 4 d ) 2 =(a+d)(a+8d)
=> d(8d-a)=0
Also, as AP is non-constant, d = 0
=> a=8d
=> AP: 8d,9d,10d...........
=> Common ratio of GP: t e r m 2 t e r m 5 = 9 d 1 2 d =1.3(approx)
Solved it the same way nice question (+1)
As our decimal evaluation allows for a 2% margin of error, I've edited the answer to be accurate to 3 significant figures.
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a + d a + 4 d = a + 4 d a + 8 d or, a + d 3 d = a + 4 d 4 d ;[dividendo] thus, a + d a + 4 d = 3 4 =1.33