Just blow it away.

Calculus Level 5

Let y = f ( x ) y=f(x) be a curve passing through ( 4 , 3 ) (4,3) such that slope of normal at any point lying in the first quadrant is negative and the normal and tangent at any point P cuts the Y a x i s Y-axis at A A & B B respectively such that the midpoint of A B AB is origin, then find the area enclosed by the curves y = f ( x ) , y = 4.25 x & y = 4.25 2.125 x y = f(x),~y=|4.25-|x||~ \& ~ y=4.25-|2.125x|


The answer is 9.833.

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