Just factor it!

$x+x^2=6$

or, $x^2+x-6=0$

or, $x^2+3x-2x-6=0$

or, $x(x+3)-2(x+3)=0$

or. $(x+3)(x-2)=0$

so now, $x=-3$ or $x=2$

so, $x=2$ ............[wanted the positive value]

x^2+x-6=0 =>x^2+3x-2x-6=0 =>x(x+3)-2(x+3)=0 =>(x+3)(x-2)=0 x=-3 or 2 Positive value of x is 2

$x + x^2 = 6 \\ x(1 + x) = 6 \\ x(1 + x) = 2 \times 3$ So, $x= 2$

$x+x^2=6$

$x^2+x-6=0$

$(x+3)(x-2)=0$

$x=-3$

$x=2$

$answer:$ $\color{#D61F06}\boxed{x=2}$