Just for fun!.

Algebra Level 1

$\large \frac 24 \times \frac 4 6 \times \frac 6 8 \times \frac 8{10} \times \ldots \times \frac{998}{1000} = ?$

\dfrac 2{1000}

\dfrac 2{800}

\dfrac 4{998}

\dfrac2{900}

1 solution

Blan Morrison
Dec 14, 2017

This problem looks very difficult at first, but it actually has a very simple solution.

If we look at the first two terms, we see that the numerator and the denominator cancel out (4). This leaves us with $\frac{2}{6}$ . If we move on to the third term, we see that we can do the same thing with the 6. This pattern continues until the very end.

The only 2 numbers that haven't been canceled out are 2 (the numerator) and 1,000 (the denominator). This leaves us with the final (but unsimplified) answer of $\frac{2}{1,000}$ .

Just for fun!.

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