Consider the 100 integers from 1 to 100 (inclusive). How many of them are perfect squares?
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1 2 = 1
2 2 = 4
3 2 = 9
4 2 = 1 6
5 2 = 2 5
6 2 = 3 6
7 2 = 4 9
8 2 = 6 4
9 2 = 8 1
1 0 2 = 1 0 0
Since the question had stated that 1 ≤ x ≤ 1 0 0
and 1 0 2 = 1 0 0
So that is 1 0 perfect squares from 1 to 100
ahhhh
Just I have done it.
i too had done this like that
Last number is 100 and √100 = 10
so total square numbers are 100/10 = 10
you need not write all square numbers and count still 1, 4, 9, 16, 25, 36, 49, 64, 81, 100 total 10
as last number is 100 you can write But if last numbers is 10000 then instead of counting find √10000 = 100
so total square numbers are 10000/100 = 100
squares of 1,2,3,4,5,6,7,8,9,and 10
1^2,2^2,3^2,4^2,5^2,6^2,7^2,8^2,9^2 and 10^2 all in all we got 10
1, 4, 9, 16, 25, 36, 49, 64, 81 and 100 are perfect squares.
There are only 10 perfect square numbers in the first 100 integers. 1, 4, 9, 16, 25, 36, 49, 64, 81 and 100. Easy
There are 10 perfect square integers between 1 and 100 (inclusive of 1 and 100)
10 (you can simply check the perfect square by multiplying the integers itself starting from 1 until the multiplication of integers itself crosses the integer 100. This is because we have to find perfect square between 1 to 100. )
1x1=1 2x2=4 3x3=9 4x4=16 5x5=25 6x6=36 7x7=49 8x8=64 9x9=81 10x10=100 only 10 integers are perfect square between 1 to 100.
count=0 for x in range(1,100): if(x**2<=100): count+=1 print(count)
100 is ten squared so it seems probable that there are 9 others...
you forgot 1 the first square number.
1^2 = 1 2^2 = 4 3^2 =9 4^2 = 16 5^2 = 25 6^2 = 36 7^2 = 49 8^2 = 64 9^2 = 81 10^2 = 100
1 1=1 2 2=4 3 3=9..........TILL 9 9=81 10*10=100 So,total number are 10
we know that square of 10 we got 100 so there are 10 pwrfect square between 1to 100
First you need to be an idiot.
sorry for this guys, i don't know to my cousin why he wrote this
ignore this. :DD
Since 1 0 0 = 1 0 2 and 1 = 1 2 , so there lies the squares of 2 to 9 between 1 and 100. Since 1 and 100 are included here and also both 1 and 100 are perfect squares, there are 10 perfect squares in the given range.
the given statement is 100 integers
solution:
1^2,2^2,3^2,4^2,5^2,6^2,7^2,8^2,9^2,10^2
totally we have 10 of them are perfect squares
10 values are perfect squares That is 1,4,9,16,25,36,49,64,81,100
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1 ≤ n 2 ≤ 1 0 0 ⇒ 1 ≤ n ≤ 1 0 , so they are 10.