I have a positive integer larger than 1 which so happens to be both a perfect square and a perfect cube.
What is the smallest possible value of this positive integer?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
First, find first power that handle multiple two and three. This is it, six . Then, two is choosen as basis we need to make it as small as possible. The answer is 2 ^ 6 = 64