Just two lines

Geometry Level 3

Line 1:- x + y = a x+y=a and

Line 2: - x / m + y / t = 1 x/m+y/t=1 are two lines, a , m , t > 0. a,m,t>0.

Area bounded by them are A 1 , A 2 , A 3. A1, A2, A3.

A 1 A1 : area between Y-axis, line 1 and line 2.

A 2 A2 : area between X-axis, line 1 and line 2

A 3 A3 : area between X-axis, Y-axis , line 1 and line 2

Which is always true?

a<t<m, A1<A2 m<t<a , A1<A2 t<m<a, A1<A2 a<m<t, A2<A1

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1 solution

Akash Shukla
May 2, 2016

x + y = a x+y=a and x / m + y / t = 1 x/m+y/t=1 Their intersecting point is [ m ( a t m t \frac{a-t}{m-t} ) , t ( a m t m \frac{a-m}{t-m} ) ]

Now, by taking determinent we can get A1 and A2.

A1 : (0,t), (0,a) , [ m ( a t m t \frac{a-t}{m-t} ) , t ( a m t m \frac{a-m}{t-m} ) ]

A2 : (m,0) , (a,0) , [ m ( a t m t \frac{a-t}{m-t} ) , t ( a m t m \frac{a-m}{t-m} ) ]

by determinent,

A1 = 1 / 2 ( m / m t ) ( a t ) 2 1/2 | (m/m-t) (a-t)^2 |\

A2 = 1 / 2 ( t / m t ) ( a m ) 2 1/2 | (t/m-t) (a-m)^2

Now, A 1 / A 2 A1/A2 = ( m / t ) [ ( a t ) / ( a m ) ] 2 | (m/t) [(a-t)/(a-m)]^2 |

now, if m < t < a m<t<a , ( a m ) > ( a t ) (a-m)>(a-t) and m < t m<t so A 1 / A 2 < 1 A1/A2<1

and for all other options it is not always true.

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