K_ip > K_sp

Chemistry Level 2

In the solution of 60ml 0.1M N a 2 S O 4 Na_{2}SO_{4} 10ml 0.2M B a ( N O 3 ) 2 Ba(NO_{3})_{2} solution is added. Will sediment of B a S O 4 BaSO_{4} fall?

D E T A I L S : K s p ( B a S O 4 ) = 1.09 × 1 0 − 10 DETAILS: K_{sp}(BaSO_{4}) = 1.09 \times 10^{-10}

No! Possibly It can't be determined Yes!

Farhabi Mojib by Farhabi Mojib , 23, Bangladesh

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1 solution

Farhabi Mojib
Nov 3, 2015

N a 2 S O 4 + B a ( N O 3 ) 2 = B a S O 4 + 2 N a N O 3 Na_{2}SO_{4}+Ba(NO_{3})_{2} = BaSO_{4} + 2NaNO_{3}
BaSO_{4}=Ba^{+}_{(aq)} + SO_{4}^{2-}_{(aq)}
K i p = [ B a 2 + ] [ S O 4 2 − ] K_{ip} = [Ba^{2+}][SO_{4}^{2-}]
= ( 10 × 0.2 70 ) ( 60 × 0.1 70 ) =(\frac{10\times0.2}{70})(\frac{60\times0.1}{70})
= 2.45 × 1 0 − 3 =2.45\times10^{-3}
So, K i p > K s p K_{ip}>K_{sp}
Therefore, sediment of B a S O 4 BaSO_{4} will fall.

0 Helpful 0 Interesting 0 Brilliant 0 Confused

Dude, you gave away the answer in the title of the question ! :P

Krishna Ar - 5 years, 6 months ago

thanks, I got it!!

Rohan K - 5 years, 6 months ago

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