KE? Momentum?

Classical Mechanics Level 1

The momentum of a bullet of mass 20 g fired from a gun is 10 kg m/s 10 \text{ kg m/s} The kinetic energy of this bullet expressed in kJ will be:


The answer is 2.5.

Vignesh Rao by Vignesh Rao , 20, India

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2 solutions

Andrew Ellinor
Feb 13, 2016

The momentum of the bullet is m v ⟶ 0.02 v = 10 ⟶ v = 500. mv \longrightarrow 0.02v = 10 \longrightarrow v = 500.

Therefore, the kinetic energy of the bullet is 1 2 m v 2 ⟶ 1 2 ( 0.02 ) ( 500 ) 2 = 2500 J = 2.5 k J \frac{1}{2}mv^2 \longrightarrow \frac{1}{2}(0.02)(500)^2 = 2500 J = 2.5 kJ

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Anup Mandal
Nov 2, 2017

KINETIC ENERGY=P^2/2m.Apply the above formula directly to get the answer

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