Keep Brilliant running

Total no. of requests in a minute= 234 * 2 * 14=6552

Servers required= 6552 / 567 = 11.55555

But since no. of servers cant be fraction so no. of required servers = 12

It's very easy: According to question: Total students present on website: 234. Each student view page/min: 2. One page sends total requests: 14.

Therefore, total request ONE STUDENT sends requests: $14 \times 2 = 28$

As we know total students available on the website: 234. So, total requests sent by all the students: $234 \times 28 = 6,552$

Also, it is given that one server can handle 567 requests/min.

So, on dividing 6,552 by 567 , we get: 11.55

Rounding off our answer (because hint says: We cannot set up a fraction of a server.):

Our Answer is: 12 Servers !

234 X 2 X 14 / 567

= 11.5555 = 12(approx.)

I used understanding and reasoning to solve this problem.Let's do it step by step.

Step 1: Find the information in the problem.

We can make these statements:

a) $1$ server can handle $567$ requests per minute.

b) $234$ students are on Brilliant website.

c) $1$ student views $2$ pages per minute.

d) $1$ page view requires $14$ requests.

Step 2: Combine the informations

Let's work backwards from statement d).

Statement d) : $1$ page view $\rightarrow14$ requests

Statement c) : $1$ student $\rightarrow2$ page views per minute

Combining the statements d) and c),

$1$ student $\rightarrow2$ page views per minute $\rightarrow14\times2=28$ requests per minute

$1$ student $\rightarrow28$ requests per minute

Statement b) : $234$ students.

$234$ students $\rightarrow28\times234=6552$ requests per minute

Statement a) : $1$ server $\rightarrow567$ requests per minute

There are $6552$ requests per minute.Therefore, Brilliant needs

$\frac{6552}{567}=11.5556\rightarrow\boxed{12}$ servers

Problem solved! :D

each server can handle = 567 reqs 234 students X 2 pages = 468 pages/min each page view requires 14 reqs X 468 = 6552 reqs/min 6552 reqs divided by each server can handle 567 = 11.5 that means to handle this Sam needs at least 12 servers

234 2 14=number of requests x. 567/x= 11.6 so need 12 servers

requests per minute 2 12=28 requests multiplied by number of students 28 234=6552 number of requests handled by servers. 6552/567=11.55 since fraction of a server cannot be set up, hence 12 servers are needed.

2 x 14 x 234 = 6552

since 1 server could handle only 567 request,

so 6552/567= 11.5

and the answer is 12 (round off 11.5)

234 students * 2 pages/min *14 equest/page = 6552 requests/min

Hence, no. of servers = 6552/567 =11.55

But , no. of servers should be integer. hence taken 12.

234 students opened 2 pages which requires 14 requests for each page. It means at that time there were (14x2x234) requests, it's 6552 requests. For 1 server can handle 567 requests, it means Sam needs (6552 / 567) servers to handle all request. It's 11,555 servers. Assume that the servers are people, they stand for 1 that means we round the number to 12 as the answer!

12

First, to find the number of pages viewed in a minute, we multiply 234 by 2. This yields a result of 468. Then, we multiply this by 14 to find the number of requests in a minute, which is 6552. We then divide this by 567 to get 11 5/9. And since Brilliant can't run fractions of a server, we round this up to get the answer of 12.

so you times 14(the number of requests) by 2(the pages per min) times 234(the number of students) divided by 567(the number of requests per min) which equals 11.55555555555555... and as they can only create hole servers the answers 12 .