Keep calm and Integrate

Calculus Level 4

π / 4 π / 3 12 csc ( 2 x ) [ ln ( sin 2 ( x ) ) ln ( cos 2 ( x ) ) ] 2 d x \int_{\pi/4}^{\pi/3}12\csc (2x)[\ln(\sin^2(x))-\ln(\cos^2(x))]^2 \, dx

If the above integral equals ( ln b ) a (\ln b)^a , where a a and b b are positive integers, find a + b a+b .


The answer is 6.

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1 solution

Harsh Shrivastava
Feb 23, 2016

K = 12 csc ( 2 x ) [ l n ( s i n 2 ( x ) ) l n ( c o s 2 ( x ) ) ] 2 d x K = \displaystyle \int 12\csc (2x)[ln(sin^2(x))-ln(cos^2(x))]^2 dx

Using properties of logarithm ,

l n ( s i n 2 ( x ) ) l n ( c o s 2 ( x ) ) = ln tan 2 x ln(sin^2(x))-ln(cos^2(x)) = \ln \tan ^{2} x

Thus our integrand becomes

K = 12 csc ( 2 x ) [ ln tan 2 x ] 2 d x K =\displaystyle \int 12\csc (2x)[\ln \tan ^{2} x]^2 dx

Now let t = l n tan 2 x t = ln \tan ^{2} x

d t d x = 4 csc 2 x \frac{dt}{dx} = 4\csc 2x

Therefor K = 3 t 2 d t K = \displaystyle\int 3t^{2} dt

Which on evaluating and substituting back t = ln tan 2 x t = \ln \tan^{2} x gives K = ln 3 tan 2 x K = \ln ^{3} \tan ^{2} x

On putting limits and evaluating, final answer becomes ln 3 3 \ln ^{3} 3

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