Keep 'em Enclosing
Starting from a single hexagon, we enclose it with contiguous hexagons that share common boundaries with it and completely submerge it in the new hexagons formed.
The first iteration has been drawn to the right. How many hexagons will be required for the second, and then the third, iteration of the same process?
To make it clearer, for the second iteration, we need to enclose all the six hexagons by drawing new hexagons around them. And then we will do it again in the third iteration.
Write the answer as two numbers separated by a decimal. For example, if the answer is 10 for second and 20 for the third iteration, your final answer should be .
The answer is 12.18.
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1 solution
As shown in the figure, for the second itineration we need 12 hexagons and, for the third, 18 . Therefore, the solution is 1 2 . 1 8